2y^2+3xy+1=0

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Solution for 2y^2+3xy+1=0 equation:


Simplifying
2y2 + 3xy + 1 = 0

Reorder the terms:
1 + 3xy + 2y2 = 0

Solving
1 + 3xy + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 3xy + -1 + 2y2 = 0 + -1

Reorder the terms:
1 + -1 + 3xy + 2y2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3xy + 2y2 = 0 + -1
3xy + 2y2 = 0 + -1

Combine like terms: 0 + -1 = -1
3xy + 2y2 = -1

Add '-2y2' to each side of the equation.
3xy + 2y2 + -2y2 = -1 + -2y2

Combine like terms: 2y2 + -2y2 = 0
3xy + 0 = -1 + -2y2
3xy = -1 + -2y2

Divide each side by '3y'.
x = -0.3333333333y-1 + -0.6666666667y

Simplifying
x = -0.3333333333y-1 + -0.6666666667y

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